Ratio of Atoms in a Compound
NOTE: Formula -> chemical formula
Empirical (Simple) Formula
Imagine you have 2 samples of a chemical containing copper and oxygen. You could have copper
The simple formula can be determined from the experimental analysis of the % composition of each element. It tells us the simplest whole-number ratio of the atoms in the compound
The simple formula is not always the Molecular True Formula, it only tells us the lowest whole number ratio.
- Mass: assume 100g, so the percentages convert nicely
- Moles: divide by molar mass
- Ratio: divide molar mass by smallest molar mass, and round
A compound is found to contain
solution
Atom | Mass (g) | Moles | Ratio |
---|---|---|---|
C | 63.1 | ||
H | 11.9 | ||
F | 25.0 |
Therefore the formula is
When 25 g of a hydrocarbon is burned, 68.58 g
Notes:
- A hydrocarbon contains only
and - During combustion a hydrocarbon reacts with
to produce and - Unbalanced combustion equation:
- All of the carbon in the hydrocarbon is converted to carbon in the
solution
Find the number of moles of
Then we have
To find the number of moles of
Then, to find the mass of
Then find the moles of
Since
Molecular (True) Formula
An ionic compound is always represented in the smallest whole number ratio, for example
Copper (II) Oxide | Magnesium Oxide |
---|---|
However, a molecular compound might not be represented in the smallest whole number ratio, so the empirical formula may not match the true molecular formula:
1:2 |
1:2 |
1:4 |
Note that
The molecular formula is always a multiple of the empirical formula
To calculate the true formula, the molar mass of the molecule MUST be provided
What is the molecular formula for a compound whose molar mass is 90 g/mol, and whose empirical was determined to be
solution
- Calculate molar mass
- Calculate the
multiple
, since the true formula is some multiple of the empirical formula - Calculate the true formula by multiplying the empirical formula coefficients by the multiple
A compound is found to contain
solution
- Determine empirical formula
so the empirical formula is - Calculate molar mass
- Calculate the multiple
- Calculate the true formula
Cortisol (
Cortisol is 69.6% C, 8.34% H, and 22.1% O by mass. What is its molecular formula?
solution
Assume 100 grams.
Ratios:
- C:
- H:
- O:
The molecular mass of an "empirical" formula constructed with these values is:
Ratio of this molar mass to the given molecular weight:
So
- C:
- H:
- O:
Molecular formula: