Convergence and Divergence
Convergence and Divergence
If we add infinitely, we may converge to a number, which is pretty crazy (we add infinitely, but still come to a number).
An infinite series of constants
Given the series
If
For example, a geometric series may converge.
Does
solution
The series is equivalent to
Convergence Tests
- #Geometric Series
- Given
:
Ifthen the series converges, otherwise it diverges
- Given
- #Divergence Test (aka Nth Term Test)
- If
, then the series diverges, otherwise we do not know anything
- If
- #Integral Test
- Conditions:
- Given
and a function which is continuous, positive, and decreasing on with :
For all, the series converges if and only if also converges.
- Conditions:
- #P-Series Test
- Given
:
The series converges if and only if
- Given
- #Comparison Test
- Conditions:
- Given
with , if we can identity another sum such that: for all , if converges, then also converges for all , if diverges, then also diverges
- Conditions:
- #Limit Comparison Test (LCT)
- Conditions:
- If
and , then and converge of diverge together.
- Conditions:
- #Alternating Series Test (AST, Leibniz Test)
- Conditions:
, the series is alternating between + and - - Given
:
Ifand the sequence is decreasing, the series converges - #Alternating Series Estimation Theorem (ASET)
- Given convergent series
, the error is bounded by
- Given convergent series
- #Absolute and Conditional Convergence
- If
converges, then is absolutely divergent - If
diverges, but converges, then is conditionally divergent
- If
- #Riemann Rearrangement Theorem (Riemann Series Theorem)
- We can rearrange the order we add a conditionally convergent series to change it's resultant sum
- Conditions:
- #Ratio Test
- Very OP
- Suppose
. Then: - If
, the series is absolutely convergent (this is related to the geometric series) - If
, we make no conclusion - If
, the series is divergent
- If
- #Root Test
- Rare. Ratio test expect with
- Rare. Ratio test expect with
Geometric Series
Recall the formula for the sum of a geometric series:
Because
For what
- If
, then - If
, then - If
, then
So our limit exists for sure for
- If
, then the limit doesn't exist - If
, then- We can't use our limit, since we specified
(we would get a 0 in the denominator), so which diverges
- We can't use our limit, since we specified
- If
, then , so the limit does not exist
converges if
Does
solution
Since
Does
solution
Since
Does
solution
but
Does
solution
Lets write it in summation notation:
Does it converge? Yes, only for
What does it converge to?
Note we got the formula of (1) from
Divergence Test (aka Nth Term Test)
In the case of a geometric series,
If
This theorem is not if and only if. Just because
We will prove the contrapositive of the statement, which states that if
Let
Does
solution
so the series diverges.
Does
solution
so the series diverges.
Does
solution
Integral Test
Applicable only to series with
(see integral)
Given
For all
Recall from Curve Sketching and Optimization that we can check if a function is decreasing by taking its derivative, if we cannot tell by inspection.
Recall that an integral is the area under a curve. As such, if the area under a curve is finite, then the curve must also be finite.
Does the series
solution
Notice that if we try the divergence test,
But
(see improper integral)
since the integral diverges, so does the series.
Does
solution
Evaluating this using the Method of Substitution,
Since the integral converges, the series also converges.
Does
solution
The integral diverges, so the series also diverges.
P-Series Test
The series:
converges if and only if
Since this is an if and only is theorem, the series will diverge if
If
Suppose
since the integral converges, so does the series.
Does
solution
Does
solution
Comparison Test
Applicable only to series with
Given the series
for all , if converges, then also converges for all , if diverges, then also diverges
Think squeeze theorem vibes. If
Does
solution
Compare this with
Does
solution
We know
Limit Comparison Test (LCT)
Applicable only to series with
If
Suppose that
Since
Similarly, we have
We have proven the desired result, which is that the series either both converge or both diverge.
Does
solution
A comparison test won't work:
But using limit comparison test:
We have
Does
solution
Compare this with
so the sum converges by limit comparison test because
Does the series
solution
Compare this with
By limit comparison test, since the series diverges.
Use the limit comparison test first, then try the comparison test
Alternating Series Test (AST, Leibniz Test)
Applicable only to series with
Consider the series
Does the series
solution
This is not a p-series, since there are negative terms. However, it is alternating, and
Does the series
solution
The series alternates, and
Alternating Series Estimation Theorem (ASET)
Given a convergent alternating series
That is, if you stop after
This means the truncation error is less than the first term omitted. In other words, the next term will "overstep" the error, so we can use it as an upper bound.
Given the Taylor Series
What is the error in
solution
This is an alternating series, so the error is bounded by the first omitted term:
Absolute and Conditional Convergence
On the one hand, alternating series are easy to handle, but there is a strange feature.
If
If
A series is conditionally convergent if and only if it is convergent, the series of its positive terms diverges to infinity, and the series of its negative terms diverges to infinity.
All non-alternating series are absolutely divergent.
Is the series
solution
This is an alternating series and the terms are decreasing.
But
Aside: This is the Taylor series of
Is the series
solution
This is an alternating series and the terms are decreasing.
The series
We are after absolute convergent series, because they behave like normal functions. Conditional convergence is fiction.
Riemann Rearrangement Theorem (Riemann Series Theorem)
What the sum converges to is conditional on the order the terms are added⁉️⁉️
Suppose the sum
There also exists
That is, if an infinite series is conditionally convergent, then its terms can be arranged in a permutation such that the new series converges to any arbitrary real number, or diverges.
Recall the conditionally divergent series:
We can change the order of terms to make the sum anything we want.
Suppose I want the sum to equal
Which is an alternating series which converges to
Why? We can keep infinitely alternating between below 1.5 and above 1.5. Think about it like a scale. One one side are the odd terms (positive) and on the other are the even terms (negative). We have infinity on both sides of the scale. Since
Conditional convergent series are a lie.
They are conditional on the order the terms are added.
There's some deity with an infinite number of weights to balance the scale to whatever they want.
- Prof. Matthew Scott
Ratio Test
This test is very powerful
Suppose
- If
, the series is absolutely convergent - If
, the test fails (we make no conclusion) - If
, the series is divergent
This tests tries to see if
The ratio test on
Does the series
solution
We could use AST, but the ratio test is easier:
so the series is absolutely convergent.
Does the series
solution
so the series is divergent.
For what values of
solution
so the series converges absolutely for all
Note that this is the Taylor polynomial for
For what values of
solution
so the series converges absolutely for
Note that this is the Taylor polynomial for
Root Test
Same as ratio test with
Suppose
- If
, the series is absolutely convergent - If
, the test fails (we make no conclusion) - If
, the series is divergent